grep - dealing with EOL

I am attempting to search through several lines of text with the following reg expression using grep:

Code:

grep -o '9[0-9] [8-9][0-9] 9[0-9].*\{40\}' sample.txt

Works but grep does not always return the following 40 characters. Instead it only returns up to 40 characters to the EOL which ever comes first.

What I am looking to do is get the following 40 characters whether there is an EOL within the following 40 characters or not.

Rather not show with what I have in sample.txt but here is the idea:

sample.txt

Code:

90 80 90 hello there

good bye

returns....

Code:

90 80 90 hello there good bye

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